Why the Oxygen dissociation curve shifts towards left side in CO poisoning? (Explain to me how the affinity of hemoglobin towards oxygen rises.)
Graph shift toward left because o2 conc inc,temp dec,H+ion conc dec,n co
The curve is shifted to right whn pO2 is low, pCO2 is high, H+ concentration, increased body temperature increases n 2, 3 diphosphoglycertae in RBC that is in tissue capillaries which favors the dissociation of oxygen frm Hb n if thr is decrease in pCO2, H+ concentration( pH is high) is low, low temperature n pO2 is increased wch favors the formation of oxyhemoglobin so the oxygen dissociation curve shifts left. Similarly CO poisoning, CO combines with Hb even more readily then with O2 ( 230 times faster) to form cherry red compound carboxyhemoglobin this reduces the amt of Hb available to carry oxygen n moreover CO is nt easily released by Hb n causes CO poisoning. Here also shift move to left bz pO2 is low, high temperature, high H+ concentration favors the formation of oxyhemoglobin n if pCO is high, high H+ concentration, high temperature n low pO2 the curve shifts left n this CO poisoning unconsciousness will occur in 1hr n death in 4 hrs. CO is dangerous bz it is odorless n victim 'll nvr knw whn CO is inhaled.
I want to tell you that I know about the Oxygen dissociation curve and what are the factors that causes the shift. You don't need to tell me that. Just tell how the affinity of hemoglobin towards oxygen increases, basically that causes the shift.
I'm sorry for the mistake the sentence is wrong. "....... Here also shift move to right bz pO2 is low, high pCO, high H+ concentration, high temperature favors the dissociation of oxygen from Hb n if pCO is high, high H+ concentration, high temperature n low pO2 the curve shifts left n this CO poisoning unconsciousness will occur in 1 hr n death in 4 hrs. CO is dangerous bz it is odorless n victim 'll nvr knw whn CO is inhaled.
